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MultiRadix.java 2.5KB

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  1. import java.util.*;
  2. /***********************************************************
  3. * Oblig 3 - sekvensiell kode, INF2440 v2017.
  4. * Ifi, Uio, Arne Maus
  5. * for store verdier av n > 100 m, kjør (f.eks):
  6. * >java -Xmx16000m MultiRadix 1000000000
  7. ************************************************************/
  8. class MultiRadix implements Sorter {
  9. int n;
  10. int [] a;
  11. final static int NUM_BIT = 7; // alle tall 6-11 .. finn ut hvilken verdi som er best
  12. public int[] sort(int[] arr) {
  13. return radixMulti(arr);
  14. }
  15. int [] radixMulti(int [] a) {
  16. long tt = System.nanoTime();
  17. // 1-5 digit radixSort of : a[]
  18. int max = a[0], numBit = 2, numDigits, n =a.length;
  19. int [] bit ;
  20. // a) finn max verdi i a[]
  21. for (int i = 1 ; i < n ; i++)
  22. if (a[i] > max) max = a[i];
  23. while (max >= (1L<<numBit) )numBit++; // antall binaere siffer i max
  24. // bestem antall bit i numBits sifre
  25. numDigits = Math.max(1, numBit/NUM_BIT);
  26. bit = new int[numDigits];
  27. int rest = (numBit%numDigits), sum =0;;
  28. // fordel bitene vi skal sortere paa jevnt
  29. for (int i = 0; i < bit.length; i++){
  30. bit[i] = numBit/numDigits;
  31. if ( rest-- > 0) bit[i]++;
  32. }
  33. int[] t=a, b = new int [n];
  34. for (int i =0; i < bit.length; i++) {
  35. radixSort( a,b,bit[i],sum ); // i-te siffer fra a[] til b[]
  36. sum += bit[i];
  37. // swap arrays (pointers only)
  38. t = a;
  39. a = b;
  40. b = t;
  41. }
  42. if (bit.length%2 != 0 ) {
  43. // et odde antall sifre, kopier innhold tilbake til original a[] (nå b)
  44. System.arraycopy (a,0,b,0,a.length);
  45. }
  46. return a;
  47. } // end radixMulti
  48. /** Sort a[] on one digit ; number of bits = maskLen, shiftet up 'shift' bits */
  49. void radixSort ( int [] a, int [] b, int maskLen, int shift){
  50. int acumVal = 0, j, n = a.length;
  51. int mask = (1<<maskLen) -1;
  52. int [] count = new int [mask+1];
  53. // b) count=the frequency of each radix value in a
  54. for (int i = 0; i < n; i++) {
  55. count[(a[i]>>> shift) & mask]++;
  56. }
  57. // c) Add up in 'count' - accumulated values
  58. for (int i = 0; i <= mask; i++) {
  59. j = count[i];
  60. count[i] = acumVal;
  61. acumVal += j;
  62. }
  63. // d) move numbers in sorted order a to b
  64. for (int i = 0; i < n; i++) {
  65. b[count[(a[i]>>>shift) & mask]++] = a[i];
  66. }
  67. }// end radixSort
  68. void testSort(int [] a){
  69. for (int i = 0; i< a.length-1;i++) {
  70. if (a[i] > a[i+1]){
  71. System.out.println("SorteringsFEIL på plass: "+i +" a["+i+"]:"+a[i]+" > a["+(i+1)+"]:"+a[i+1]);
  72. return;
  73. }
  74. }
  75. }// end simple sorteingstest
  76. }// end SekvensiellRadix