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MultiRadix.java 2.8KB

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  1. import java.util.*;
  2. /***********************************************************
  3. * Oblig 3 - sekvensiell kode, INF2440 v2017.
  4. * Ifi, Uio, Arne Maus
  5. * for store verdier av n > 100 m, kjør (f.eks):
  6. * >java -Xmx16000m MultiRadix 1000000000
  7. ************************************************************/
  8. class MultiRadix{
  9. int n;
  10. int [] a;
  11. final static int NUM_BIT = 7; // alle tall 6-11 .. finn ut hvilken verdi som er best
  12. int [] radixMulti(int [] a) {
  13. long tt = System.nanoTime();
  14. // 1-5 digit radixSort of : a[]
  15. int max = a[0], numBit = 2, numDigits, n =a.length;
  16. int [] bit ;
  17. // a) finn max verdi i a[]
  18. //Timer ta = new Timer().start();
  19. for (int i = 1 ; i < n ; i++)
  20. if (a[i] > max) max = a[i];
  21. while (max >= (1L<<numBit) )numBit++; // antall binaere siffer i max
  22. //System.out.println("A: "+ta.end().prettyTime());
  23. // bestem antall bit i numBits sifre
  24. numDigits = Math.max(1, numBit/NUM_BIT);
  25. bit = new int[numDigits];
  26. int rest = (numBit%numDigits), sum =0;;
  27. // fordel bitene vi skal sortere paa jevnt
  28. for (int i = 0; i < bit.length; i++){
  29. bit[i] = numBit/numDigits;
  30. if ( rest-- > 0) bit[i]++;
  31. }
  32. int[] t=a, b = new int [n];
  33. for (int i =0; i < bit.length; i++) {
  34. radixSort( a,b,bit[i],sum ); // i-te siffer fra a[] til b[]
  35. sum += bit[i];
  36. // swap arrays (pointers only)
  37. t = a;
  38. a = b;
  39. b = t;
  40. }
  41. if (bit.length%2 != 0 ) {
  42. // et odde antall sifre, kopier innhold tilbake til original a[] (nå b)
  43. System.arraycopy (a,0,b,0,a.length);
  44. }
  45. return a;
  46. } // end radixMulti
  47. /** Sort a[] on one digit ; number of bits = maskLen, shiftet up 'shift' bits */
  48. void radixSort ( int [] a, int [] b, int maskLen, int shift){
  49. int acumVal = 0, j, n = a.length;
  50. int mask = (1<<maskLen) -1;
  51. int [] count = new int [mask+1];
  52. // b) count=the frequency of each radix value in a
  53. //Timer tb = new Timer().start();
  54. for (int i = 0; i < n; i++) {
  55. count[(a[i]>>> shift) & mask]++;
  56. }
  57. //System.out.println("B: "+tb.end().prettyTime());
  58. // c) Add up in 'count' - accumulated values
  59. //Timer tc = new Timer().start();
  60. for (int i = 0; i <= mask; i++) {
  61. j = count[i];
  62. count[i] = acumVal;
  63. acumVal += j;
  64. }
  65. //System.out.println("C: "+tc.end().prettyTime());
  66. // d) move numbers in sorted order a to b
  67. Timer t = new Timer().start();
  68. for (int i = 0; i < n; i++) {
  69. b[count[(a[i]>>>shift) & mask]++] = a[i];
  70. }
  71. t.end();
  72. System.out.println("seq D: "+t.prettyTime());
  73. }// end radixSort
  74. void testSort(int [] a){
  75. for (int i = 0; i< a.length-1;i++) {
  76. if (a[i] > a[i+1]){
  77. System.out.println("SorteringsFEIL på plass: "+i +" a["+i+"]:"+a[i]+" > a["+(i+1)+"]:"+a[i+1]);
  78. return;
  79. }
  80. }
  81. }// end simple sorteingstest
  82. }// end SekvensiellRadix